Question

Three resistance of 3,4 and 5 ohms are joined in parallel in an electric circuit .if a current of 150 mA flows through the resistor of 4 ohms , then calculate the values of the current in mA which will be flowing through the other two resistors.

Answer 1

Let us look at the answer:

Explanation:

Three resistors of 3, 4 and 5 ohms are joined in parallel.

the net equivalent resistance 1/R= 1/3 + 1/4 + 1/5 = 20+15+12/60 ⇒ R = 60/47

In parallel arrangement, voltage is same and the current is different for each resistor.

For 4 ohms, V = IR = 150×10⁻³ × 4 = 600 × 10⁻³ = 0.6 V

For 3 ohm resistor, I = V/R = 0.6 / 3 = 0.2 A

For 5 ohm resistor, I = V/R = 0.6/ 5 = 1.2 A