three resistance of 3ohm 4ohm 6ohm are connected in parallel. the combination is connected to a cell of emf 2V and internal resistance 2/3ohm . find the current drawn from the cell and the current through 3ohm
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Eq resistance, of parallel combination 4,6 and 12 ohm resistors from relation 1/R = 1/R1 + 1/R2 + 1/R3, is
1/{1/4+1/6+1/12} = 1/(3/12+2/12+1/12) = 1/(3+2+1)/12 = 1/6/12 = 2 ohm.
Total resistance connected to battery = 2+2 = 4
battery current = 4/4 = 1 amp
1/{1/4+1/6+1/12} = 1/(3/12+2/12+1/12) = 1/(3+2+1)/12 = 1/6/12 = 2 ohm.
Total resistance connected to battery = 2+2 = 4
battery current = 4/4 = 1 amp
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