Question

Three resistances 1 12 and 3 ohms are connected a) in series b)in parallel what rezistance will they offer

Answer 1

Answer:

Series = 16 ohms

Parallel = 12/17 ohms

Explanation:

Given :

• Resistances of 1, 12 and 3 ohms are connected in series and parallel

To find :

• Resistances offered by them in both the cases

Series :

Req = R1+R2+R3

Req = 1+12+3

Req = 16 ohms

Parallel :

1/Req = 1/R1 + 1/R2 + 1/R3

1/Req = 1/1 + 1/12 + 1/3

1/Req = 12/12 + 1/12 + 4/12

1/Req = 17/12

Req = 12/17

The resistance offered in series umis equal to 16 ohms and in parallel is equal to 12/17 ohms

Answer 2

Given:

• Three resistors of 1 ohm , 12 ohm , 3 ohm

To find:

• Resistance when connected in i) series ii) parallel

Solution:

Let

• Resistor 1 be R1
• Resistor 2 be R2
• Resistor 3 be R3

a) series:

We know that

When 3 resistors are connected in series

Rs = R1 + R2 + R3

Rs = 1 + 12 + 3

Rs = 16 ohm

Hence , the resistors when connected in series we get resistance of 16 ohm

b) Parallel:

We know that

When three resistors are connected in parallel

1/Rp = 1/R1 + 1/R2 + 1R3

1/Rp = 1/1 + 1/12 + 1/3

1/Rp = 1 + (1 + 4)/12

1/Rp = 1 + 5/12

1/Rp = 17/12

Rp = 12/17

Hence, the resistors when connected in parallel we get resistance of 12/17 ohm