Three resistances 2 Ω , 4 Ω and 6 Ω are connected in series .find the resultant resistance
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Explanation:
The arrangement of three resistors of 2,3Ω and 6Ω which gives a total resistance of 4Ω can now be represented as follows: Thus, we can obtain a total resistance of 4Ω by connecting parallel combination of 3Ω and 6Ω resistors in series with 2Ω resistor
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Answer:
as three resistors are in series connection so the resultant would be addition of three
2ohm+4ohm+6ohm=12 ohm(answer)
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