Question

three resistances each of 5 ohm are connected to form a triangle.calculate the resistance between two ends of any arm​

Answer 1

Given Three resistances each of 5 ohm are connected to form a triangle.calculate the resistance between two ends of any arm​

here the resistors are connected to form an equilateral triangle. The third resistor is connected in parallel, while the other two are in series

So for series we have R1 + R2 = 5 + 5 = 10 ohm

Now we calculate the resistance for the two corners of the triangle by

1 / R parallel = 1/R1 + 1/R2

1/R Parallel = 1/10 + 1/5

1/R Parallel = 1 + 2 / 10

1/R Parallel = 3 / 10

Two ends of the arm is given by

R = 10 / 3 ohms = 3.33 ohms