Question

Three resistances of 1Ω each are connected in parallel. Such a connection is again
connected with a 1/3Ω resistor in series. Find the equivalent resistance of the circuit.

Answer 1

Answer:

For parallel combination of n equal resistance R, each R

eq

=

n

R

Resistance of 1 ohm group =

n

R

=

3

1

Ω

This is in series with

3

2

Ω resistor

∴ Total resistance =

3

2

+

3

1

=

3

3

Ω=1Ω