Three resistances of 2ohm, 4ohm and 5ohm are connected in series. What is its resultant resistance?
Answers
Answered by
6
let R1=2 ohm,R2=4 ohm,R3=5 ohm
since the resistance are connected in series, the resultant resistance is equal to the sum of the resistance applied in the circuit.
Rs=R1+R2+R3
=2+4+5
=11 ohm
Answered by
2
Given : three resistors of resistance 2 ohms, 4 ohms and 5ohms are connected in series,
To Find : Resultant resistance
Solution:
R₁ = 2 Ω
R₂ = 4 Ω
R₃ = 5 Ω
connected in series,
Hence resistances will be added
Rtotal = R₁ + R₂ + R₃
=> Rtotal = 2 + 4 + 5
=> Rtotal =11 Ω
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