Question

three resistances of 4 ohm 6 ohm and 10 ohm are connected in series the potential difference across the combination is 5 volt calculate the potential difference across each resistor​

Answer 1

According to ohm’a law

V=IR

R= r1+r2+r3

R=4+6+10

R=20 ohm

Total resistance in series connection= 20 ohm

V=IR

I=V/R

I=5/20

I=0.25 A

In series connection, current through each resistor is same

Let V1,V2 and V3 be the potential differences across resistors r1 ,r2 and r3 respectively

V1= I*r1=0.25*4= 1 volt

V2 = I* r2=0.25*6=1.5 volt

V3= I/r3=0.25*10=2.5 volt

Answer 2

Answer:

voltage=5v

R1=5

R2=6

R3=10 so Re=5+6+10=21

Ohms law I=V/R

5/21=0.23 so

0.23×5=1.15 ohm

0.23×6=1.38

0.23×10=2.3 Done hope it helps u...