three resistor 1 ohms 2 ohms 3 ohms are combined in series what is the total resistance of the combination?
b) if the combination is connected to a battery of emf 12 v and negligible internal resistance obtain the potential drop actors each resistor
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a) In series combination÷
R = R1+R2+R3....
R = 1+2+3 = 6
R = R1+R2+R3....
R = 1+2+3 = 6
Ranaarsharsh:
b) part solve karne ka koi hint ya solution haa
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