three resistor 5,10,and 30 ohm are connected in parallel with battery of 6 V find the total current
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V / R = 6 / 30 = 0.2 Ampere . B ] TOTAL CURRENT IN CIRCUIT. R = 30 / 10 = 3Ω . [ TOTAL CURRENT ( I ) = V / R = 6 / 3 = 2 AMPERE ] .
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Answer:
Explanation:
TOTAL CURRENT IN PARALLEL COMBINATION= SUM OF INDIVIUAL CURRENTS
POTENTIAL DIFFERENCE=6 V
FIRST RESISTOR= I=V/R = 6/5 = 1.2
SECOND RESISTOR= 6/10 =0.6
THIRD RESISTOR= 6/30 = 0.2
TOTAL CURRENT=1.2+0.6+0.2
=2 AMPERE
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