Question

Three resistor of 2 ohm 3 ohm and 6 ohm are connected in parallel circulate the total resistance

Answer 1

Given :

• Three resistor of 2 ohm 3 ohm and 6 ohm are connected in parallel connection.

To find :

• Total resistance or Equivalent resistance

Formula used :

$\dfrac{1}{Req} = \dfrac{1}{R1} + \dfrac{1}{R2} + \dfrac{1}{R3} ......$

the above Formula is only for parallel connection.

where :-

• Req = equivalent resistance

• R1 , R2 and R3 = resistance of resistors connected in parallel connection

Solution :

In parallel connection we know that :-

$\dfrac{1}{Req} = \dfrac{1}{R1} + \dfrac{1}{R2} + \dfrac{1}{R3}$

Now put :-

• R1 = 2
• R1 = 3
• R3 = 6

$\implies\dfrac{1}{Req} = \dfrac{1}{2} + \dfrac{1}{3} + \dfrac{1}{6}$

LCM of 2 , 3 and 6 = 6

Now :-

$\implies\dfrac{1}{Req} = \dfrac{3+2+1}{6}$

$\implies\dfrac{1}{Req} = \dfrac{6}{6}$

Now we will out 6 from numerator and denominator :-

$\implies\dfrac{1}{Req} = 1$

Answer :

Req = 1 ohm

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Learn more :-

If resistors are connected in series connection then we can use the following formula to get Equivalent resistance :-

Req = R1+ R2 + R3..........

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