Physics, asked by vigneshwar01, 8 months ago

Three resistors 10 ohm, 10 ohm, and 5 ohm connected in parallel. The effictive resistance will be *

2 ohm
2.5 ohm
5 ohm
10 ohm​

Answers

Answered by Anonymous
23

Three resistors 10 ohm, 10 ohm and 5 ohm are connected in parallel.

Let's denote 10 ohm by R1 another 10 ohm resistor by R2 and 5 ohm resistor by R3. All of them are connected in parallel as shown:

----------------| R1 |----------------

----------------| R2 |----------------

----------------| R3 |----------------

We have to find the effective resistance of these three resistors.

Req = 1/R1 + 1/R2 + 1/R3

Req = (R1 + R2 + R3)/(R1R2R3)

Req = R1R2R3/(R1 + R2 + R3) ......(1st equation)

For series combination:

Rs = R1 + R2 + R3

But in question we are talking about parallel combination. So,

For parallel combination:

1/Rp = 1/R1 + 1/R2 + 1/R3

1/Rp = (R1 + R2 + R3)/(R1R2R3)

Rp = R1R2R3/(R1 + R2 + R3) ......(2nd equation)

Substitute the known values,

1/Rp = 1/10 + 1/10 + 1/5

Take L.C.M. as 10

1/Rp = (1 + 1 + 2)/10

1/Rp = 4/10

Rp = 10/4

Rp = 2.5 ohm

From (1st equation) and (2nd equation) we can say that,

Req = Rp

Req = 2.5 ohm

Therefore, the effective resistance is 2.5 ohm.

Option (b) 2.5 ohm

Answered by ShivamKashyap08
24

Answer:

  • The Effective Resistance will be 2.5 Ω

Given:

  1. Given resistance:- 10 Ω, 10 Ω and 5 Ω.

Explanation:

_______________________________

As given there are Three resistors which are connected in Parallel.

From the Formula, we know,'

1/R = 1/R₁ + 1/R₂ + 1/R₃

Here,

  • R Denotes Effective resistance.
  • R₁ is given resistance.
  • R₂ is given resistance.
  • R₃ is given resistance.

Substituting the values,

⇒ 1/R = 1/10 + 1/10 + 1/5

Taking L.C.M

⇒ 1/R = ( 1 + 1 + 2 )/10

⇒ 1/R = 4/10

Reciprocating it,

⇒ R = 10/4

⇒ R = 2.5

R = 2.5 Ω

The Effective Resistance will be 2.5 Ω.

Hence 2nd Option is correct !

_______________________________

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Some Formulas:

  1. For Series connection: R = R₁ + R₂ ..... + Rₓ
  2. V = I R
  3. P = V² / R
  4. P = V I
  5. H = I² R t
  6. H = ( V² / R ) t

Note:

  • Symbols have their usual meanings.

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