Three resistors 4ohm, 12ohm and 6 ohm are connected in parallel. If the total current
taken is 12 A, find the current through each resistors.
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Answer:
Explanation:
its so simple
Add All resistors dn from their sum subtract the output current
4+12+6= 22 Ohm
So the current passed through each register will be
22-12= 10A
Good Luck
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