Three resistors are in parallel circuit. Resistor 1 measures 5 ohms, the second resistor has 6 ohms and a 3A current flows in it. If the total current is 11.5 A, determine (a) the reading on ammeter and (b) the value of the third resistor.
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Answer:
I2= 2.5 ohms -> reading on the ammeter
Value of the resistor(R3) -> 2.5 ohms
Explanation:
Given:
R1 = 5 ohms
R2 = 6 ohms
R3 = ?
Current 1 (I1) = 3 A
Total current (IS) = 11.5 A
a) V = I1R1
= 3 x 5
= 15 V
The voltage is same in parallel
V = I2R2
I2 = V/R2
= 15/6
= 2.5 A
Calculating the current in third resistance
IS = I1 + I2 + I3
11.5 = 3 + 2.5 + I3
11.5 - 5.5 = I3
I3 = 6 A
b) Value of the third resistor
R3 = V/I
= 15/6
= 2.5 A
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