Question

Three resistors of 1 ohm ,2 ohm,3 ohm are connected in series with a battery of 12 V as shown in fig . Values of potential difference V1,V2,V3 across the three resistors have resistors have respective values:
a)2V,4V,6V. b)6V,4V,2V

c)3V,2V,1V d)1/12V,2/12V,3/12V

Explain briefly..​

Answer 1

Answer: a)

Explanation:

They are in series combination

so, Equivalent resistance = 3 + 2 + 1

= 6 ohm

Now, By ohm's law V = iR

I = V/R

i = 12 /6

i = 2 Ampere

Current across 1 ohm V = i×1

V = 2volt

Current across 2 ohm V = i × 2

V = 4Volt

Current across 3 ohm V = i × 3

V = 6 Volt

Hope it helps.....✌

Answer 2

Option(a) is the correct answer.

.2V, 4V, 6V

Given:

Three resistors of 1 ohm, 2 ohms, and 3 ohms are connected in series, and the voltage of the battery is 12 V.

To find:

The values of potential differences V1, V2, and V3 of resistors.

Solution:

Resistance of the first resistor= 1 ohm

Resistance of the second resistor=2 ohm

Resistance of the third resistor= 3 ohm

The total resistance in series is the sum of the resistance of all resistors.

So, the total resistance=1+2+3=6 ohm

The total voltage of the battery= 12V

By Ohm's law,

V=iR, I is the total current

12=I(6)

I=2 ampere

Now, each resistor has a current of 2A.

So, each resistor will have,

By using Ohm's law,

V1=iR1

V1=2×1

=2 Volts

Similarly,

V2=2×2, V3=2×3

=4 V, 6 V

So, the potential differences are 2V, 4V, and 6 V.

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