Question

Three resistors of 12 ,15 and 20 ohms are connected first in series and then in parallel. What is the equivalent resistance in each case ​

Answer 1

AnSwer :

According to Question,

R₁ = 12Ω

R₂ = 15Ω

R$_3$ = 20Ω

When resistor is connected in series,

The combined of any number of resistance connected in series is equal to the sum of the individual resistances.

${\to {\bf{R_s = R_1 + R_2 + R_3 }}}$

${\to {\bf{R_s =12 + 15 + 20}}}$

${\to { \boxed{\bf{R_s = 47Ω }}}}$

the equivalent resistance when connected in series is 47Ω.

when resistors are connected in parallel,

The reciprocal of the combined resistance of a number of resistance connected in parallel is equal to the sum of the reciprocals of all the individual resistances.

${\to{\bf{\dfrac{1}{R_p} =\dfrac{1}{R_1}+ \dfrac{1}{R_3} + \dfrac{1}{R_3} }}}$

${\to{\bf{\dfrac{1}{R_p} =\dfrac{1}{12}+ \dfrac{1}{15} + \dfrac{1}{20} }}}$

${\to{\bf{\dfrac{1}{R_p} =\dfrac{5 + 4 + 3}{60} }}}$

${\to{\bf{\dfrac{1}{R_p} =\dfrac{12}{60} }}}$

${\to{\bf{\dfrac{1}{R_p} =\dfrac{1}{5} }}}$

${\to{ \boxed{\bf{{R_p} =5Ω }}}}$

the equivalent resistance when connected in parallel is 5Ω.

Answer 2

Explanation:

ᴛʜʀᴇᴇ ʀᴇꜱɪꜱᴛᴏʀꜱ ᴏꜰ ᴍᴀɢɴɪᴛᴜᴅᴇꜱ 12 Ω, 15 Ω ᴀɴᴅ 20 Ω ᴀʀᴇ ᴄᴏɴɴᴇᴄᴛᴇᴅ ɪɴ (ɪ) ꜱᴇʀɪᴇꜱ ᴀɴᴅ (ɪɪ) ᴘᴀʀᴀʟʟᴇʟ. ᴄᴀʟᴄᴜʟᴀᴛᴇ ᴛʜᴇ ᴄᴏᴍʙɪɴᴇᴅ ʀᴇꜱɪꜱᴛᴀɴᴄᴇ ɪɴ ᴇᴀᴄʜ ᴄᴀꜱᴇ. = 47 Ω.

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘꜱ ᴜʜ...ᴍᴀʀᴋ ɪᴛ ᴀꜱ ʙʀᴀɪɴɪᴇꜱᴛ ᴘʟᴇᴀꜱᴇ..!!

$THᴀ᭄NK UH..♥️$