Question

three resistors of 15 ohom, 25 ohom & 10 ohom are connected in series. combination. voltes 20 then find current ​

Answer 1

Answer:just add the resistance of the resistors and divide it with the voltage V

Explanation:Given,

V = 20v

R1 = 15 ohm

R2= 25 ohm

R3 = 10 ohm

Therefore, the total resistance,

R = R1+R2+R3

R = 15+25+10

R = 50 ohm

Now, we know tha V=IR

Therefore, I=V/R

I=20/50

I=2/5

I=0.4A. Answer

Answer 2

Given :-

★ Three resistors of 15 Ω, 25 Ω and 10 Ω are connected in series.

★ Potential difference of 20 volts is applied through the combination.

To Find :-

★ The current flowing through circuit.

Solution :-

We know,

the equivalent Resistance is given by

Rs = R1 +R2 +R3 +......... +Rn

According to the question :-

R1 = 15 Ω

R2 =25 Ω

R3 =10 Ω

Substituting the given values, we get

Rs = R1 +R2 +R3

⟹ Rs =( 15 +10 +25) Ω

⟹ Rs = 50 Ω

☞ Ohm's law

V =IR

Where,

V = Voltage

R = Resistances

I = Current

Now, put the given values

I = 20/50

⟹ I =0.4 A

Hence,

the value of current flowing through circuit is = 0.4 A.

Know More :-

✰What is series combination?

=> When current flow only one direction not change, it said to be series combination.

✰ What is parallel combination?

=> When current flow different direction, it said to be parallel combination.

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