Question

Three resistors of 2,3,4 ohms connected parallel to each other across a battery of 10 V,calculate the current flowing in all the three resistors.​

Answer 1

since the three resistors , shown in th circuit have been joined in parllel , hence voltage across each of them is same having a value V = 10 V.

therefore, current I 1 through resistance R1 = 2 ohms,

I1 = V/R1 = 10/2 = 5A

current I2 through resistance R2 = 3 ohms ,

I2 = V/R2 = 10/3 = 3.3A

current I3 through resistance R3 = 4 ohms ,

I3 = V/R3 = 10/4 = 2.5A

Total current flowing through the circuit is I = I1 +I2 + I3 = 5 + 3.3 + 2.5 = 10.8.