three resistors of 2, 4 and 6 ohm are connected in(i) series and(ii) parallel what will be the two components offer
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Explanation:
1) three resistor are connected in series,
Rs = R1 + R2 + R3
=( 2 + 4 + 6 ) ohm
= 12 ohm
2) three resistor are connected in parallel,
RP = 1/R1 + 1/R2 + 1/R3
= 1/2 + 1/4 + 1/6
= 11/12 ohm
= 1.09 ohm
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