Three resistors of 3Ω are connected in series combinations, the equivalent
resistance is R, then connected in parallel equivalent resistance is R2. Find R1|R2
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so series = r1+r2+r3= req
therefore 3+3+3=9
parallel = 1/r1+1/r2=1/rep
therefore 1/3+1/3+1/3= 3/3= 1
r1/r2 = 9/1=9
Explanation:
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