Question

Three resistors of resistance 2 ohm 3 ohm 4 ohm are joined 1.in series 2.in parallel in each case find equivalent resistance

Answer 1

Answer:

Explanation:

In series:-

$R_{eq} = R_{1} + R_{2} + R_{3}$

THUS,

$R_{eq}$ = (2 + 3 + 4) Ω

     = 9 Ω

In parallel:-

$\frac{1}{R_{eq} } = \frac{1}{R_{1} } + \frac{1}{R_{2} } + \frac{1}{R_{3} }$

$\frac{1}{R_{eq} } = \frac{1}{2} + \frac{1}{3} + \frac{1}{4}$

$\frac{1}{R_{eq} } = \frac{13}{12} \\R_{eq} = \frac{12}{13}$

$R_{eq}$   = 0.92 Ω