Three resistors of resistance 2ohm,3ohm,5ohm are connected in the series. Calculate the effective resistance of the combination
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Rs= R1+R2+R3
=2+3+5= 10ohms
=2+3+5= 10ohms
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answer will be 10ohm because in series resistors can connected directly without varying current like ,R(n) = R1+R2+R3
in same way R(n)= 5ohm+3ohm+2ohm, = (10ohm) will be ur answer
HOPE IT WILL HELP
in same way R(n)= 5ohm+3ohm+2ohm, = (10ohm) will be ur answer
HOPE IT WILL HELP
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