Question

three resistors of resistance R1 R2 and R3 are connected in first in series and second in parallel write expressions for the equivalent resistance of the combination in each case two identical resistors of 12 ohm each are connected to a battery of 3 volt calculate the ratio of the power consumed by the resulting combinations with the minimum resistance and maximum resistance​

Answer 1

i know the final answer ....i.e.

4:1 is the ratio.

Answer 2

According to the given details, there are three resistors available with the resistance of  R1, R2 and R3.

In the series connection, the equivalent resistance is 12+12=24 ohm

Power = V2/R = 100/24 = 4 W

In the parallel connection, the equivalent resistance is (12x12)/(12+12) = 6 ohm

Power = V2/R = 100/6 = 16 W

Required power = 4:16 = 1:4