3x+5y=12 ,Express the given linear equation in the form of ax+by+c=0 and indicate the values of a, b and c in each case.
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Answered by
12
3x+5y-12=0
now by comparing it to
ax+by+c=0
we get
a=3
b=5
c=-12
now by comparing it to
ax+by+c=0
we get
a=3
b=5
c=-12
Answered by
4
Given linear equation
3x + 5y = 12
=> 3x + 5y - 12 = 0
=> 3x + 5y + ( -12 ) = 0
Compare this with ax+by+c=0
We get ,
a = 3 , b = 5 , c = -12
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