x/3+y/4=7,Express the given linear equation in the form of ax+by+c=0 and indicate the values of a, b and c in each case.
Answers
Answered by
8
4x+3y=84
4x+3y-84=0
is rhe required equation
now by comparing it to ax+by+c=0
a=4
b=3
c=-84
4x+3y-84=0
is rhe required equation
now by comparing it to ax+by+c=0
a=4
b=3
c=-84
Answered by
16
Given linear equation is
x/3 + y/4 = 7
LCM of 3 , 4 = 12
Multiply each term with 12 ,
We get
12x/3 + 12y/4 = 12 × 7
=> 4x + 3y = 84
=> 4x + 3y - 84 = 0
=> 4x + 3y + ( -84 ) = 0
Compare this with ax+by+c=0
we get
a = 4 , b = 3 , c = -84
••••
Similar questions