Question

three resistors of resistored values 80 ,120,and 240 and connected in the paralal in equipment across a supply voltage of 240 find the current through each resistors and then find the total connected taken by the equipment.​

Answer 1

Answer:

$\frac{1}{rp } = \frac{1}{80} + \frac{1}{120} + \frac{1}{240} \\ \frac{1}{rp} = \frac{6}{240} \\ rp \: = \frac{240}{6} \\ rp = 40$

total current = V/R = 240/40 =6 amp

Explanation:

I1= 240/80=3amp

I2= 240/120=2amp

I3= 240 /240=1amp

Answer 2

Explanation:

r1=80, r2=120, r3=240

v=240

solution:

v =i×r

i1=v÷r1

= 240÷80

i1=3A

i2=v÷ r2

=240÷120

i2=2A

i3=v÷r3

=240÷240

i3=1A

Total Current=i1+ i2 +i3

=3+2+1

=6A