Three resitors r½ampere 4 ampere are connected in series in a circuit if the result resistance in the circuit is 20 ampere. find the value of R
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The current in the circuit is calculated from the formula I=
R+r
ε
where,
ε- emf of the cell
R- external resistance
r- internal resistance of the cell.
When the cell of internal resistance of 3 ohms and the total current in the circuit is given as 0.25 A the current relation is given as
That is, 0.25=
R+3
2
.
The Resistance is R=5Ω
Hence, the total resistance in the circuit is 5 ohms, out which one resistor is 4 ohms. So, the unknown combined resistance is 5−4=1Ω.
The potential difference across the 2 ohms or R resistor is given as V=IR=0.25A×1Ω=0.25V
Thus, the p.d. across the R or 2 ohms resistor is 0.25 V.
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