Three rods of the same mass are placed as shown in the figure. What will be the co-ordinates of the center of mass of
the system?
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for a rod its center of mass is mid point of this rod.
So the CM of vertical rod will be (0,2a)
the CM of horizontal rod will be (2a,0)
the CM of inclined rod will be (2a,2a)
so the center of mass of the system will be at x=m+m+mm(0+0.5a+0.5a)=3a
and y=m+m+mm(0.5a+0+0.5a)=3a
or at (3a,3a)
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