Three sets of 336 english books, 240 mathematics books and 96 science books have to be stacked in such a way that all the books are stored subjectwise and the height of each stack is the same. total number of stacks will be:
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hcf (each stack) = hcf (336, 240, 96)
=48
no of stacks of maths book
no of stacks of english book = 7
no of stacks of maths book = 5
no of stacks of science book = 2
total stacks = 14
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hcf (each stack) = hcf (336, 240, 96)
=48
no of stacks of maths book
no of stacks of english book = 7
no of stacks of maths book = 5
no of stacks of science book = 2
total stacks = 14
HOPE IT HELPS YOU
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1
Answer:
In order to arrange the books as required, we have to find the largest number that divides 96, 240 and 336 exactly. Clearly, such a number is their HCF Computation of 96, 240 and 336.
\begin{gathered}96 = 2 \times 2 \times 2 \times 2 \times 2 \times 3 \\ 240 = 2 \times 2 \times 2 \times 2 \times 3 \times 5 \\ 336 = 2 \times 2 \times 2 \times 2 \times 3 \times 7\end{gathered}
96=2×2×2×2×2×3
240=2×2×2×2×3×5
336=2×2×2×2×3×7
Therefore the HCF is 48.
Stacks of English books = 96/48 = 2
Stacks of Hindi books = 240/48 = 5
Stacks of Maths books = 336/48 = 7
Step-by-step explanation:
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