Three sides of a triangle are a, 3a and 3a. Find the measurement of angle opposite to the largest side.
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Let In △ ABC, AB = a, BC = 3a and AC = 10−−√ a
Now, AB2 + BC2 = a2 + (3a)2 = a2 + 9a2 = 10a2and AC2 = (10−−√ a)2 = 10 a2Since AB2 + BC2 = AC2 then, △ ABC is a right angled △.Such that ∠B = 90° [By the converse of pythagoras theorem]∴ AC is the longest side of △ ABC & the angle opposite to the longest side is 90°.
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90 degree.
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