Question

Three similar coins are tossed for a large number of times.the probability of getting two heads and one tail uppermost is

Answer 1

P=(HHH,HHT,HTH,THH,TTT,TTH,THT,HTT)
Therefore, the probability of getting two heads and one tail uppermost isTHREE.

Answer 2

Answer:

0.375 is the probability of getting two heads and one tail uppermost .

Step-by-step explanation:

• Probability of an event occurring P(E) = Number of favourable outcomes/Total Number of outcomes

• To find : Two heads and one tail probability

• Total number of outcomes = $2^{3} = 8$

• $(HHH,TTT,HTT,THT,TTH,THH,HTH,HHT)$ all are possible outcomes.

• Number of favourable outcomes getting two heads and one tail are
• $(THH,HTH,HHT)$, three in number.
• Probability is defined as the number of favourable outcomes divided by the total number of conceivable outcomes.

Thus the required probability is $=$ $\frac{3}{8}$

                                                    $= 0.375$

As a result, the likelihood of two heads and one tail when three coins are tossed is 3/8.

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