Question

Three solid cubes of sides 1cm, 6cm and 8 cm are melted to form a new cube. Find the surface area of cube so formed.​

Answer 1

Answer:

$total \: volume \: of \: cubes = ( {1}^{3} + {6}^{3} + {8}^{3} ) = (1 + 216 + 512) = {729cm}^{3}$

$volume \: of \: the \: new \: cube = 729 {cm}^{3}$

$side \: of \: the \: new \: cube = \sqrt[3]{729} = 9cm$

$surface \: area = (6 \times {9}^{2} ) = (6 \times 81) = 486 {cm}^{2}$

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Answer 2

Answer:

${1296cm}^{3}$

Step-by-step explanation:

Volume = l×b×h

Volume = 1×6×8

$volume \: = \: {48cm}^{3}$

48cm^3 for one cube.

Three cubes are melted to form one cube. So;

length(l) , height(h) and width(b)/(w) of the new formed cube will be three times .

Volume of new formed cube will be:

Volume = l× b× h

Volume = (1×3) × (6×3) × (8×3)

Volume = 1296cm^3