Three solid metal cubes, whose edges measure 3 cm, 4 cm and 5 cm are melted to form a single cube. Find the lateral surface area and total surface area of the new cube assuming that there is no wastage.
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Given,
side of three solid cubes
s1=3cm, s2=4cm, and s2=5cm
Volume of three cubes = Volume of largest cube
v1+v2+v3 =V
(3)^3 +(4)^3 +(5)^3 = (S)^3
27+ 64+ 125 = (S)^3
216 = (S)^3
S= 6 cm
Lateral surface area of new cube= 4(S)^2
= 4*(6)^2
= 4*36
= 144 sq. cm
Total surface area of new cube= 6*(S)^2
= 6*(6)^2
= 6*36
= 216 sq. cm
Hope it will help you.
side of three solid cubes
s1=3cm, s2=4cm, and s2=5cm
Volume of three cubes = Volume of largest cube
v1+v2+v3 =V
(3)^3 +(4)^3 +(5)^3 = (S)^3
27+ 64+ 125 = (S)^3
216 = (S)^3
S= 6 cm
Lateral surface area of new cube= 4(S)^2
= 4*(6)^2
= 4*36
= 144 sq. cm
Total surface area of new cube= 6*(S)^2
= 6*(6)^2
= 6*36
= 216 sq. cm
Hope it will help you.
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