three solid metal cubes with edges 6cm,8cm and 10cm respectively are melded together and formed into a single cube.find the voume of new cube
Answers
Answered by
2
Volume remains same so
volume of new cube = v1+v2+v3
= 6^3+8^3+10^3
=216+512+1000
=1728
now volume of new cube = a^3= 1728
edge of new cube = a= cuberoot of 1728
a= 12
therefore surface area of new cube = 6 a^2
=6×12^2
=6×12×12
=864 square cm
volume of new cube = v1+v2+v3
= 6^3+8^3+10^3
=216+512+1000
=1728
now volume of new cube = a^3= 1728
edge of new cube = a= cuberoot of 1728
a= 12
therefore surface area of new cube = 6 a^2
=6×12^2
=6×12×12
=864 square cm
Answered by
1
Hey friend your answer is
~~~~~~~~~~~~~~~~~~~~~~~
Q:-Three solid metal cubes with edges 6cm, 8 cm and 10cm respectively are melted together and formed into a single cube find the volume of the new cube.
Method of solution
-----------------------------
side of cube 1 = 6cm
volume of cube 1 =(6×6×6)cm³=216cm³
side of cube 2=8cm
volume of cube 2 = (8×8×8)cm³=512cm³
side of cube 3= 10cm
volume of cube 2= (10×10×10)cm³=1000cm³
Volume of metal of 3 cubes
=(216+512+1000)cm³
=1728cm³
•°•Volume of new cube =1728cm³
•°•side of new cube = ³√1728cm³
= ³√12×12×12cm
=12cm
~~~~~~~~~~~~~~~~~~~~~~~
Q:-Three solid metal cubes with edges 6cm, 8 cm and 10cm respectively are melted together and formed into a single cube find the volume of the new cube.
Method of solution
-----------------------------
side of cube 1 = 6cm
volume of cube 1 =(6×6×6)cm³=216cm³
side of cube 2=8cm
volume of cube 2 = (8×8×8)cm³=512cm³
side of cube 3= 10cm
volume of cube 2= (10×10×10)cm³=1000cm³
Volume of metal of 3 cubes
=(216+512+1000)cm³
=1728cm³
•°•Volume of new cube =1728cm³
•°•side of new cube = ³√1728cm³
= ³√12×12×12cm
=12cm
Similar questions
Geography,
7 months ago
Math,
7 months ago
Math,
1 year ago
History,
1 year ago
Political Science,
1 year ago