Question

Three sparingly soluble salts M2X, MX
and MX3, have same value of solubility
product. Their solubilities follow the
order:
(1) MX3> MX > M2X
(2) MX > MX3> M2X
(3), MX > M2X > MX3
(4) MX3 > M2X > MX​

Answer 1

Answer:

3

Explanation:

The lesser the solubility product lesser is the solubility

Answer 2

Their solubilities follow the  order: $MX$ > $M_2X$ > $MX_3$

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as $K_{sp}$

1. For $M_2X$

The equation for the ionization of $M_2X$ is given as:

$M_2X\leftrightharpoons 2M^{+}+X^{2-}$

$K_{sp}=[M^{+}]^2[X^{2-}]$

$K_{sp}=[(2s)^2][(s)]=4s^3$

2.  For $MX$

The equation for the ionization of $MX$ is given as:

$MX\leftrightharpoons M^{+}+X^{-}$

$K_{sp}=[M^{+}][X^{-}]$

$K_{sp}=[s][(s)]=s^2$

3. For $MX_3$

The equation for the ionization of $MX_3$ is given as:

$MX_3\leftrightharpoons M^{3+}+3X^{-}$

$K_{sp}=[M^{3+}][X^{-}]^3$

$K_{sp}=[s][(3s)^3]=27s^4$

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