Question

) Three strings of lengths 50 m 75 cm, 68 m 58 cm and 121 m 3 cm, respectively, are joined
together to get a single string of greatest length, find the length of the single string obtained.
If this single string is then divided into 12 equal pieces, find the length of each piece.



please explain with statements and please show working​

Answer 1

Answer:

The length of the single string obtained = 240 m 36 cm

The length of each piece = 20 m 3 cm

Step-by-step explanation:

Given :

Three strings of lengths :

50 m 75 cm = 5075 cm

68 m 58 cm = 6858 cm

121 m 3 cm = 12103 cm

Here, Three strings are joined together to get a single string of greatest length.

The length of the single string obtained = Sum of the length of the Three strings.

= (5075 + 6858 + 12103) cm

= 24036 cm

= 240 m 36 cm

Now, This single string is then divided into 12 equal pieces.

The length of each piece = 24036/12 = 2003 cm

= 20 m 3 cm

Answer 2

Answer:

Given :-Three strings of length 50m 75cm, 68m 58cm, 121m 3cm respectively

First convert all the measurements in cm

50m = 5,000 cm

75cm

68m = 6,800 cm

58cm

121m = 12,100 cm

3 cm

Length of first string=5,000+75=5,075 cm

Length of second string=6,800+58=6,858 cm

Length of third string=12,100+3=12,103 cm

To find :- Length of single string

obtained by joining all strings

= Sum of all string

=5,075 + 6,858 + 12,103

=24,036 cm

To find length of a single string if it is divided into 12 equal parts

=24,036

-----------

12

=2,003 cm

=2m 3cm

Each string will be of 2m 3cm