Question

Three students start jogging together on a circular track.If they respectively take 6 minutes,8 minutes and 12 minutes to complete one round when will they meet again?

Answer 1

Step-by-step explanation:

Let the students be A,B and C

Time taken by A=6 min

". " by B=8 min

". ". by C= 12 min

take L.C.M of all three numbers 6,8,12

which is 24

ANS: they will meet again in 24 min

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Answer 2

Answer:

The students will meet again after 24 minutes.

OR

The students will meet again when Student1 completes 4 rounds,  Student2 completes 3 rounds and Student3 completes 2 rounds.

Step-by-step explanation:

The students will meet again after $LCM(6, 8, 12)$ minutes.

∴ 6 = 2 x 3

8 = 2 x 2 x 2 = 2³

12 = 2 x 2 x 3 = 2² x 3

∴ LCM = 2³ x 3 = 24 minutes

∴ The students will meet again after 24 minutes.

∴ Student1 completes $\frac{24}{6}$ = 4 rounds.

Student2 completes $\frac{24}{8}$ = 3 rounds.

Student3 completes $\frac{24}{12}$ = 2 rounds.

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