Question

three substances A,Band C melt at 0.C ,50.C and -150 .C respectively and their boiling points are 100.C 200 .C and 10.C .State the physical nature of A,B and C at room temperature​

Answer 1

Explanation:

• Substance A

MP=0°C and BP=100°C

Thus, it would be Liquid at Room Temperature

• Substance B

MP=50°C and BP=200°C

Thus, it would be Solid at Room Temperature

• Substance C

MP= -150°C and BP=10°C

Thus, it would be Gaseous at Room Temperature

• REASON :-
• Substance A is Liquid because it Freezes at 0°C but Room Temp. is More than that .
• Substance B is Solid because it Freezes at 50°C but Room Temp. is much lower than that.
• Substance C is Gas because it boils at just 10°C and Room Temp. is well above that