Question

Three successive natural frequencies of an organ pipe are 225Hz,385Hzand525Hz. If the speed of sound is 330 m/s the of pipe of

Answer 1

Explanation:

Given Three successive natural frequencies of an organ pipe are 225 Hz,385 Hz and 525 Hz. If the speed of sound is 330 m/s the length of pipe is

• Now the frequencies are 225, 385 and 525
• Taking out factors we get
• 225 = 5 x 5 x 3 x 3
• 385 = 5 x 7 x 11
• 525 = 5 x 5 x 3 x 7
• Therefore the highest common factor is 5
• Now we have the ratio as 45 : 77 : 105 for a closed organ pipe.
• So fundamental frequency is 5 hz
• Now l = v / 4f      (v = λf)
• So l = 340 / 5 x 4
• Or l = 340 / 20
• Or l = 17 m