Question

Three symmetrical dice are thrown. The probability of having different points on them is

Answer 1

Probability of having different points on three dice = 1 − Probability of having same points on the dice

Cases when same points on the dice:

Case 1: When all points are same: 1 1 1, 2 2 2, 3 3 3, 4 4 4, 5 5 5, 6 6 6 =6 cases

Case 2: When two points are same and one is different:

(11−): 5 and we could arrange on three ways so 15 cases are there

Similarly for (22−);(33−);......(66−).

Total cases when two points are same and one is different: 15×6=90

Total cases when same points on the dice: 6+90=96

Probability of having different points on three dice =1−6×6×696=95

Answer 2

Answer:

5 / 9

Step-by-step explanation:

first 3 die s....for Dice 1 --probability is 6 / 6

                     for Dice 2--probability is 5 / 6

                     for Dice 3--probability is 4 / 6

thus total probability is  6 / 6    x     5 / 6     x    4 / 6   =    20 / 36  =  5 / 9