Question

three tankers contain 187l ,231l,275l liters of petrol respectivly using euclids division algorithm find the capacity of the largest container that can measure the petrol of three tankers exact no of time

Answer 1

I think answer is:
187×231=43197
then, 43197 minus 275 = 42922 is the answer....... Hope it helps......

Answer 2

we have

petrol in first tanker=187L

petrol in second tanker=231L

petrol in third tabker=275L

The capacity of the largest container that can measure the petrol of the three containers exact no. of times =HCF(187L,231L,275L)

Applying Euclid's algorithm to187and231 ,we get

231=187×1+44

187=44×4+11

44=11×4+0

clearly, HCF of 187&231is11.

Now,we find the HCF of 11 &275,we get. 275=11×25+0

clearly,HCF of 275&11 is11.

Hence, the required capacity of the largest container that can measure the petrol of the three tankers exact no. of times is11L. ANSWER

HOPE THIS WILL HELP YOU.