Math, asked by Megha2782, 1 year ago

Three taps A, B and C together can fill an empty cistern in 10 minutes. The tap A alone can fill it in 30 minutes and the tap B alone in 40 minutes. How long will the tap C alone take to fill it?
A.16 minutes
B.24 minutes
C.32 minutes
D.40 minutes

Answers

Answered by panigrahiraj
13

Answer:

B-24mins

Step-by-step explanation:

Three taps(A+B+C) can fill in 1 minute=1/10 of the cistern

A fill in in 1 min=1/30 of the cistern

B fill in 1 mins =1/40 of the cistern

A=B together in 1 min=1/30+1/40=7/120 of the cistern

C in 1 min can fill=1/10-7/120 = 5/120=1/24 of the cistern

Hence, C can fill up the tank= 1/(1/24)=24mins

Answered by ramsir47
3
the answer of the question is 24 minutes...
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