Question

three terms of the sequence below. T n = 2 n 2 + 5 n − 3

Answer 1

Answer:

Three terms of the sequence $T_{n} =2n^{2} +5n-3$ is,

$T_{1} =4\\\\T_{2} =15\\\\T_{3} =30$

Step-by-step explanation:

We can find the three terms simply by substituting for

$n=1,2,3$ in   $T_{n} =2n^{2} +5n-3$

therefore,

$T_{1} =2(1)^{2} +5(1)-3=2+5-3=4\\\\T_{2} =2(2)^{2} +5(2)-3=8+10-3=15\\\\T_{3} =2(3)^{2} +5(3)-3=18+15-3=30$

Hence the answer

thank you

Answer 2

Answer:

The answer is 4,15,30

Step-by-step explanation:

Given general(nth) term of the sequence is

                 $\text{T}_n=2n^2+5n-3$

Therefore,

First term $=\text{T}_1=2(1)^2+5(1)-3=2+5-3=4$

                (Replace n by 1 to get first term )

Second term $=\text{T}_2=2(2)^2+5(2)-3=8+10-3=15$

                (Replace n by 2 to get second term )

Third term $=\text{T}_3=2(3)^2+5(3)-3=18+15-3=30$

                (Replace n by 3 to get third term )