three times number added by 8 then the result is 19 right in equal form equal form for this data
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2
Let the number be x.
Then, According to question,
![3 \times x + 8 = 19 3 \times x + 8 = 19](https://tex.z-dn.net/?f=3+%5Ctimes+x+%2B+8+%3D+19)
![= > 3x + 8 = 19 = > 3x + 8 = 19](https://tex.z-dn.net/?f=+%3D+%26gt%3B+3x+%2B+8+%3D+19)
![= > 3x = 19 - 8 = > 3x = 19 - 8](https://tex.z-dn.net/?f=+%3D+%26gt%3B+3x+%3D+19+-+8)
![= > 3x = 11 = > 3x = 11](https://tex.z-dn.net/?f=+%3D+%26gt%3B+3x+%3D+11)
![= > x = \frac{11}{3} = > x = \frac{11}{3}](https://tex.z-dn.net/?f=+%3D+%26gt%3B+x+%3D+%5Cfrac%7B11%7D%7B3%7D+)
![\boxed{\red{Hence, \: the \: number \: is \: 11/3}} \boxed{\red{Hence, \: the \: number \: is \: 11/3}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cred%7BHence%2C+%5C%3A+the+%5C%3A+number+%5C%3A+is+%5C%3A+11%2F3%7D%7D)
Hope it helps you..
Then, According to question,
Hope it helps you..
Answered by
1
let the number be x
three times number=3x
since, three times of number added by 8 give 19
therefore, 3x+8=19
3x=19-8
3x=11
![x = \frac{11}{3} x = \frac{11}{3}](https://tex.z-dn.net/?f=x+%3D++%5Cfrac%7B11%7D%7B3%7D+)
x=3.6666666667
three times number=3x
since, three times of number added by 8 give 19
therefore, 3x+8=19
3x=19-8
3x=11
x=3.6666666667
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