three times the smallest of three consecutive odd number decreased by 7 equal twince the largest one find the numbers????????
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Step-by-step explanation:
Let three consecutive odd no. be x , x+2, x+4
A/q, 3 times smallest no. decreased by 7 = 2 times the largest
3(x) - 7 = 2(x+4)
3x - 7 = 2x+8
3x - 2x = 8+7
x = 15
The numbers are
x = 15
x+2 = 17
x+4 = 19
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Answer:
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