Question

three times the smallest of three consecutive odd number decreased by 7 equal twice the largest one find the number

Answer 1

Let the three consecutive odd number be x,x + 2, x + 4.

It is given that 3 times the smallest of 3 consecutive odd numbers decreased by 7 equals twice the largest one.

3x - 7 = 2(x + 4)

3x - 7 = 2x + 8

3x = 2x + 15

3x - 2x = 15

x = 15

x + 2 = 11 + 2 = 17

x + 4 = 11  + 4 = 19


Therefore the numbers = 15,17,19.


Hope this helps!

Answer 2

Answer:

15, 17 and 19 

Step-by-step explanation:

Numbers are n, n+2 and n+4 

3n-7 = 2(n+4) 

3n-7 = 2n+8 

3n-2n = 8+7 

n = 15 

Answer: 15, 17 and 19