Question

three times the smallest of three consecutive odd number decreased by 7 equal twice the largest one. Find the number

Answer 1

numbers are as x,x+2,x+4 largest=x+4 smallest=x

so, 3x-7=2(x+4)
3x-7=2x+8
3x-2x=8+7
x=15

therefore,first no.=x=15
second no.=x+2=15+2=17
third no.=x+4=15+4=19

15,17,19 ans

Answer 2

Answer:

Step-by-step explanation:

Let the three consecutive odd number be x,x + 2, x + 4.

It is given that 3 times the smallest of 3 consecutive odd numbers decreased by 7 equals twice the largest one.

3x - 7 = 2(x + 4)

3x - 7 = 2x + 8

3x = 2x + 15

3x - 2x = 15

x = 15

x + 2 = 11 + 2 = 17

x + 4 = 11  + 4 = 19

Therefore the numbers = 15,17,19.

Hope this helps!