three times the smallest of three consecutive odd numbers decreased by 7 equal twice the largest one. find the numbers
Answers
Answered by
10
Let the smallest number be x
other two are x+2 and x+4
by the condition given in your question we get the equation
3 (x)-7=2 (x+4)
3x-7=2x+8
x=15
so the numbers are 15,17&19
other two are x+2 and x+4
by the condition given in your question we get the equation
3 (x)-7=2 (x+4)
3x-7=2x+8
x=15
so the numbers are 15,17&19
Answered by
3
let the numbers be X,X+2,X+4
Smallest no. is x
3x- 7 = 2* (X+4)
3x- 7 = 2x+8
X=15
the numbers are 15,17,19
Smallest no. is x
3x- 7 = 2* (X+4)
3x- 7 = 2x+8
X=15
the numbers are 15,17,19
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