three times the square of a number when added to seven times the number results in 26 the number is
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Let the number be x
Hence 3x^2+7x=26
Or, 3x^2+7x-26=0
Or, 3x^2+13x-6x-26=0
Or, x(3x+13)-2(3x+13)=0
Or, (3x+13)(x-2)=0
either 3x+13=0
Or, 3x=-13
Or, x=-13/3
/OR x-2=0
Or, x=2
hence x=2,-13/3
Hence 3x^2+7x=26
Or, 3x^2+7x-26=0
Or, 3x^2+13x-6x-26=0
Or, x(3x+13)-2(3x+13)=0
Or, (3x+13)(x-2)=0
either 3x+13=0
Or, 3x=-13
Or, x=-13/3
/OR x-2=0
Or, x=2
hence x=2,-13/3
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