Three unbiased coins are tossed together. find the probability of getting:
(i) All heads
(ii) Atleast two heads
(iii) almost two tails
(iv) two tails
Answers
Answered by
1
Possible outcomes:
HHH
HTT
HTH
HHT
TTT
THH
THT
TTH
P(all heads) = 1/8
P(atleast 2 heads) = 4/8 = 1/2
P(atmost 2 tails) = 7/8
P(2 tails) = 3/8
Hope this helps :)
Answered by
0
Possible outcome swill be
2^3 = 8 which will be
HHH
HHT
HTH
HTT
THH
THT
TTH
TTT
THEREFORE
P(ALL HEAD ) = 1/8
P (ATLEAST 2 HEAD ) = 4/8 = 1/2
P(ATMOST 2 HEAD ) = 7/8
P(ATMOST 2 TAIL ) = 7/8
P(2 TAILS ) = 4/8 = 1/2
2^3 = 8 which will be
HHH
HHT
HTH
HTT
THH
THT
TTH
TTT
THEREFORE
P(ALL HEAD ) = 1/8
P (ATLEAST 2 HEAD ) = 4/8 = 1/2
P(ATMOST 2 HEAD ) = 7/8
P(ATMOST 2 TAIL ) = 7/8
P(2 TAILS ) = 4/8 = 1/2
Similar questions
Computer Science,
6 months ago